Integer.opBinary

Undocumented in source. Be warned that the author may not have intended to support it.
  1. auto opBinary(T rhs)
  2. auto opBinary(Integer!(U, E2) rhs)
    struct Integer(T, char E)
    const
    opBinary
    (
    string op
    U
    char E2
    )
    (
    Integer!(U, E2) rhs
    )
    if (
    signed == rhs.signed &&
    op.among(binOps)
    )

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